RC oscillator question

I’m trying to understand how to select the RC values for an IC that uses an RC network ( CD4541BE - CMOS Programmable Timer ).

The data sheet indicates:

The RC oscillator, shown in figure 2, oscillates with a frequency determined by the RC network and is calculated using:

f = 1 / ( 2.3 * Rtc * Ctc )

Where f is between 1khz and 100khz and Rs >= 10k and Rs ~= 2 * Rtc

Figure 2 is:

image

My question is about the value for Rs. The circuit uses a potentiometer for Rtc (10k) in order to adjust the timer (Rs is a 20k resistor). However, according to the data sheet, Rs should be around 2 * Rtc. If using a pot for Rtc, it means the design rule of Rs ~= 2 * Rtc is violated for at least 50% of the range.

Question: Is Rs mainly there to provide a high impedance path for the feedback loop? or does it take part in the frequency calculation as well ( i.e. Rs should change with Rtc in order to have a predetermined frequency )?

Empirical testing shows that Rs does indeed affect the frequency… :unamused:

So, according to the schematic in your post, one end of Rs is connected to
the buffer input and should be modelled as an open circuit, basically
(~10^12 ohms, crazy high).

For it to have any effect on the frequency, you’d expect there to be some
significant leakage in the input, so I took a look at the datasheet. It
doesn’t have any input impedance specified, so you wouldn’t expect it to
matter.

I also worked out the logic on that snippet you posted, and it didn’t make
any sense!

Googled for a drop-in replacement to see what other manufacturers were
doing:
https://www.fairchildsemi.com/datasheets/CD/CD4541BC.pdf

Also no input impedance listed, but that schematic is different! The TI one
is missing a bubble, they totally got it wrong and it makes the circuit not
work out as drawn.

tl;dr I have no idea how to solve your problem, but TI should stop hiring
interns and maybe try a replacement from a different manufacturer?